I saw the Cerebrate solve the first Scripting Games challenge: Pairing off. And immediately thought "I can do that in Haskell too".

So, here it is.

import Data.List

cards = [(1,7),(0,5),(3,7),(2,7),(2,13)]

countpairs [] = 0
countpairs [a] = 0
countpairs (a:as) = length . filter (((snd a)==) . snd) $ as

pairingOff = sum . map countpairs . tails

And that's that. Alas, the actual competition only takes Perl, VBScript and PowerShell, so I won't be submitting this.